§ 2. Задание 100. «Алгебра. 7 класс. Учебник для общеобразовательных организаций» АЛГЕБРА 7 ГДЗ Задание 100

    Задание 100

    Выполните действия:

      • $${\largeа)}\ {-}3{,}28+1{,}75;$$
      • $${\largeб)}\ {-}4{,}8+({-}0{,}48);$$
      • $${\largeв)}\ 3{,}17-({-}0{,}63);$$
      • $${\largeг)}\ {-}0{,}48\cdot({-}0{,}55);$$
      • $${\largeд)}\ {-}0{,}35:0{,}2;$$
      • $${\largeе)}\ {-}0{,}35:0{,}03;$$
      • $${\largeж)}\ 0{,}25\cdot({-}0{,}32);$$
      • $${\largeз)}\ {-}4{,}6-3{,}2.$$

    Источник заимствования: Алгебра. 7 класс. Учебник для общеобразовательных организаций / – Просвещение, 2013. – 28 c. ISBN 978-5-09-027739-6
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    Решение:

      • $${\largeа)}\ {-}3{,}28+1{,}75={-}(3{,}28-1{,}75)={-}1{,}53$$

      • $$\begin{array}{r}-\begin{array}{r}3{,}28\\1{,}75\\\hline\end{array}\\\begin{array}{r}1{,}53\end{array}\end{array}$$

      • $${\largeб)}\ {-}4{,}8+({-}0{,}48)={-}5{,}28$$

      • $$\begin{array}{r}+\begin{array}{r}4{,}80\\0{,}48\\\hline\end{array}\\\begin{array}{r}5{,}28\end{array}\end{array}$$

      • $${\largeв)}\ 3{,}17-({-}0{,}63)=3{,}17+0{,}63=3{,}8$$

      • $$\begin{array}{r}+\begin{array}{r}3{,}17\\0{,}63\\\hline\end{array}\\\begin{array}{r}3{,}80\end{array}\end{array}$$

      • $${\largeг)}\ {-}0{,}48\cdot({-}0{,}55)=0{,}264$$

      • $$\begin{array}{r}\times\begin{array}{r}0{,}48\\0{,}55\\\hline\end{array}\phantom{0}\\\begin{array}{r}+\begin{array}{r}240\\240\phantom{0}\\\hline\end{array}\\\begin{array}{r}0{,}2640\end{array}\end{array}\end{array}$$

      • $${\largeд)}\ {-}0{,}35:0{,}2={-}1{,}75$$

      • $$\begin{array}{l}\begin{array}{r}-\begin{array}{l}3{,}5\phantom{0}\\2\\\hline\end{array}\begin{array}{|l}2\\\hline1{,}75\end{array}\\\end{array}\\\begin{array}{r}-\begin{array}{r}15\\14\\\hline\end{array}\end{array}\\\phantom{0}\begin{array}{r}-\begin{array}{r}10\\10\\\hline\end{array}\end{array}\\\phantom{0000}\begin{array}{r}0\end{array}\end{array}$$

      • $${\largeе)}\ {-}0{,}35:0{,}03={-}11{,}(6)$$

      • $$\begin{array}{l}\begin{array}{r}-\begin{array}{l}35\phantom{000}\\3\\\hline\end{array}\begin{array}{|l}3\\\hline11{,}666{...}\end{array}\\\end{array}\\\phantom{0}\begin{array}{r}-\begin{array}{r}5\\3\\\hline\end{array}\end{array}\\\phantom{0}\begin{array}{r}-\begin{array}{r}20\\18\\\hline\end{array}\end{array}\\\phantom{00}\begin{array}{r}-\begin{array}{r}20\\18\\\hline\end{array}\end{array}\\\phantom{000}\begin{array}{r}-\begin{array}{r}20\\18\\\hline\end{array}\end{array}\\\phantom{000000}\begin{array}{r}20{...}\end{array}\end{array}$$

      • $${\largeж)}\ 0{,}25\cdot({-}0{,}32)={-}0{,}08$$

      • $$\begin{array}{r}\times\begin{array}{r}0{,}25\\0{,}32\\\hline\end{array}\phantom{0}\\\begin{array}{r}+\begin{array}{r}50\\75\phantom{0}\\\hline\end{array}\\\begin{array}{r}0{,}0800\end{array}\end{array}\end{array}$$

      • $${\largeз)}\ {-}4{,}6-3{,}2={-}(4{,}6+3{,}2)=-7{,}8$$

      • $$\begin{array}{r}+\begin{array}{r}4{,}6\\3{,}2\\\hline\end{array}\\\begin{array}{r}7{,}8\end{array}\end{array}$$

    Задание 99Задание 101