Задание 352

Решение:

• \({\largeа)}\ (a-b)^2=(a-b)(a-b)=a^2-ab-ab+b^2=a^2-2ab+b^2\)
• \(\phantom{\largeа)}\ (a-b)^2=a^2-2ab+b^2\)

• \({\largeб)}\ (x-3)^2=(x-3)(x-3)=x^2-3x-3x+9=x^2-6x+9\)
• \(\phantom{\largeб)}\ (x-3)^2=x^2-2\cdot{x}\cdot3+3^2=x^2-6x+9\)

• \({\largeв)}\ (1-m)^2=(1-m)(1-m)=1-m-m+m^2=1-2m+m^2\)
• \(\phantom{\largeв)}\ (1-m)^2=1^2-2\cdot1\cdot{m}+m^2=1-2m+m^2\)

• \({\largeг)}\ (5+p)^2=(5+p)(5+p)=25+5p+5p+p^2=25+10p+p^2\)
• \(\phantom{\largeг)}\ (5+p)^2=5^2+2\cdot5\cdot{p}+p^2=25+10p+p^2\)

• \({\largeд)}\ (2a-3)^2=(2a-3)(2a-3)=4a^2-6a-6a+9=4a^2-12a+9\)
• \(\phantom{\largeд)}\ (2a-3)^2=(2a)^2-2\cdot2a\cdot3+3^2=4a^2-12a+9\)

• \({\largeе)}\ (4-3y)^2=(4-3y)(4-3y)=16-12y-12y+9y^2=16-24y+9y^2\)
• \(\phantom{\largeе)}\ (4-3y)^2=4^2-2\cdot4\cdot3y+(3y)^2=16-24y+9y^2\)

• \({\largeж)}\ (3m+2n)^2=(3m+2n)(3m+2n)=9m^2+6mn+6mn+4n^2=9m^2+12mn+4n^2\)
• \(\phantom{\largeж)}\ (3m+2n)^2=(3m)^2+2\cdot3m\cdot2n+(2n)^2=9m^2+12mn+4n^2\)

• \({\largeз)}\ (5p-2q)^2=(5p-2q)(5p-2q)=25p^2-10pq-10pq+4q^2=25p^2-20pq+4q^2\)
• \(\phantom{\largeз)}\ (5p-2q)^2=(5p)^2-2\cdot5p\cdot2q+(2q)^2=25p^2-20pq+4q^2\)