Задание 353

Решение:

• \({\largeа)}\ (a-b^2)^2=a^2-2ab^2+(b^2)^2=a^2-2ab^2+b^4\)

• \({\largeб)}\ (x^3-y)^2=(x^3)^2-2x^3y+y^2=x^6-2x^3y+y^2\)

• \({\largeв)}\ (m^3-n^2)^2=(m^3)^2-2m^3n^2+(n^2)^2=m^6-2m^3n^2+n^4\)

• \({\largeг)}\ (p^4+q^2)^2=(p^4)^2+2p^4q^2+(q^2)^2=p^8+2p^4q^2+q^4\)

• \({\largeд)}\ (a^3+ab)^2=(a^3)^2+2a^3ab+(ab)^2=a^6+2a^4b+a^2b^2\)

• \({\largeе)}\ (x^3-y^2z)^2=(x^3)^2-2x^3y^2z+(y^2z)^2=x^6-2x^3y^2z+y^4z^2\)

• \({\largeж)}\ (2m-n^2)^2=(2m)^2-2\cdot2mn^2+(n^2)^2=4m^2-4mn^2+n^4\)

• \({\largeз)}\ (3p^2-2q^3)^2=(3p^2)^2-2\cdot3p^2\cdot2q^3+(2q^3)^2=9p^4-12p^2q^3+4q^6\)

• \({\largeи)}\ (4a^2b-3ab^2)^2=(4a^2b)^2-2\cdot4a^2b\cdot3ab^2+(3ab^2)^2=16a^4b^2-24a^3b^3+9a^2b^4\)