Задание 491

Решение:

• \({\largeа)}\ \frac{\vphantom{x^2}ax-bx}{cx+dx}=\frac{ x(a-b)}{ x(c+d)}=\frac{a-b}{c+d};\)
• \({\largeб)}\ \frac{\vphantom{x^2}ac+bc}{mc+nc}=\frac{ c(a+b)}{ c(m+n)}=\frac{a+b}{m+n};\)
• \({\largeв)}\ \frac{x^2}{x^2+xy}=\frac{x\cdot{x}}{ x(x+y)}=\frac{x}{x+y};\)
• \({\largeг)}\ \frac{\vphantom{x^2}ab}{a-ab}=\frac{a\cdot{b}}{ a(1-b)}=\frac{b}{1-b};\)
• \({\largeд)}\ \frac{m^2n}{m^2n-mn^2}=\frac{mn\cdot{m}}{ mn(m-n)}=\frac{m}{m-n};\)
• \({\largeе)}\ \frac{\vphantom{x^2}ax-bx}{xy+x^2}=\frac{ x(a-b)}{ x(y+x)}=\frac{a-b}{y+x};\)
• \({\largeж)}\ \frac{p^2-p}{ap-bp}=\frac{ p(p-1)}{ p(a-b)}=\frac{p-1}{a-b};\)
• \({\largeз)}\ \frac{x^2-xy}{2xy+2x^2}=\frac{ x(x-y)}{ x(2y+2x)}=\frac{x-y}{2y+2x}.\)