Задание 499

Решение:

• \({\largeа)}\ \frac{x}{x-2}\) и \(\frac{1}{2-x}={-}\frac{1}{x-2}\)

• \({\largeб)}\ \frac{x}{5+x}\) и \(\frac{3}{x+5}=\frac{3}{5+x}\)

• \({\largeв)}\ \frac{4x}{x-1}\) и \(\frac{2-7x}{1-x}={-}\frac{2-7x}{x-1}=\frac{7x-2}{x-1}\)

• \({\largeг)}\ \frac{2x}{3x+6}=\frac{2x^{\backslash1}}{ 3(x+2)\phantom{^{\backslash1}}}=\frac{2x}{ 3(x+2)}\) и \(\frac{5^{\backslash3}}{x+2\phantom{^{\backslash3}}}=\frac{3\cdot5}{ 3(x+2)}=\frac{15}{ 3(x+2)}\)

• \({\largeд)}\ \frac{15}{2x-8}=\frac{15^{\backslash1}}{ 2(x-4)\phantom{^{\backslash1}}}=\frac{15}{ 2(x-4)}\) и \(\frac{7^{\backslash2}}{x-4\phantom{^{\backslash2}}}=\frac{2\cdot7}{ 2(x-4)}=\frac{14}{ 2(x-4)}\)

• \({\largeе)}\ \frac{3-x^{\backslash2}}{5-x\phantom{^{\backslash2}}}=\frac{ 2(3-x)}{ 2(5-x)}=\frac{6-2x}{ 2(5-x)}\) и \(\frac{5}{2x-10}=\frac{5}{ 2(x-5)}={-}\frac{5^{\backslash1}}{ 2(5-x)\phantom{^{\backslash1}}}={-}\frac{5}{ 2(5-x)}\)