§ 2. Задание 98. «Алгебра. 7 класс. Учебник для общеобразовательных организаций» АЛГЕБРА 7 ГДЗ Задание 98

    Задание 98

    Сравните числа:

      • \({\largeа)}\ \frac{3}{8}\) и \({-}\frac{5}{9};\)
      • \({\largeб)}\ {-}\frac{3}{5}\) и \({-}\frac{4}{5};\)
      • \({\largeв)}\ {-}\frac{3}{7}\) и \(0;\)
      • \({\largeг)}\ \frac{8}{9}\) и \(0;\)
      • \({\largeд)}\ {-}\frac{5}{28}\) и \({-}\frac{1}{7};\)
      • \({\largeе)}\ {-}\frac{13}{24}\) и \({-}\frac{17}{26};\)
      • \({\largeж)}\ {-}\frac{98}{97}\) и \({-}\frac{99}{98};\)
      • \({\largeз)}\ {-}\frac{97}{98}\) и \({-}\frac{98}{99};\)
      • \({\largeи)}\ {-}\frac{1}{3}\) и \(\frac{{-}1}{3};\)
      • \({\largeк)}\ \frac{2}{7}\) и \(\frac{{-}2}{{-}7};\)
      • \({\largeл)}\ {-}\frac{1}{5}\) и \(\frac{1}{{-}5};\)
      • \({\largeм)}\ \frac{3}{4}\) и \({-}\frac{3}{4}.\)

    Источник заимствования: Алгебра. 7 класс. Учебник для общеобразовательных организаций / – Просвещение, 2013. – 28 c. ISBN 978-5-09-027739-6
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    Решение:

      • \({\largeа)}\ \frac{3}{8}>{-}\frac{5}{9};\)
      • \({\largeб)}\ {-}\frac{3}{5}>{-}\frac{4}{5};\)
      • \({\largeв)}\ {-}\frac{3}{7}<0;\)
      • \({\largeг)}\ \frac{8}{9}>0;\)
      • \({\largeд)}\ {-}\frac{5}{28}<{-}\frac{1}{7};\)
        \(\phantom{\largeд)}\ {-}\frac{1}{7}={-}\frac{4}{28}\)
        \(\phantom{\largeд)}\ {-}\frac{5}{28}<{-}\frac{4}{28}\)
      • \({\largeе)}\ {-}\frac{13}{24}>{-}\frac{17}{26};\)
        \(\phantom{\largeе)}\ {-}\frac{13}{24}={-}\frac{169}{312}\)
        \(\phantom{\largeе)}\ {-}\frac{17}{26}={-}\frac{204}{312}\)
        \(\phantom{\largeе)}\ {-}\frac{169}{312}>{-}\frac{204}{312}\)
      • \({\largeж)}\ {-}\frac{98}{97}<{-}\frac{99}{98};\)
        \(\phantom{\largeж)}\ {-}\frac{98}{97}={-}\frac{9604}{9506}\)
        \(\phantom{\largeж)}\ {-}\frac{99}{98}={-}\frac{9603}{9506}\)
        \(\phantom{\largeж)}\ {-}\frac{9604}{9506}<{-}\frac{9603}{9506}\)
      • \({\largeз)}\ {-}\frac{97}{98}>{-}\frac{98}{99};\)
        \(\phantom{\largeз)}\ {-}\frac{97}{98}={-}\frac{9603}{9702}\)
        \(\phantom{\largeз)}\ {-}\frac{98}{99}={-}\frac{9604}{9702}\)
        \(\phantom{\largeз)}\ {-}\frac{9603}{9702}>{-}\frac{9604}{9702}\)
      • \({\largeи)}\ {-}\frac{1}{3}=\frac{{-}1}{3};\)
      • \({\largeк)}\ \frac{2}{7}=\frac{{-}2}{{-}7};\)
      • \({\largeл)}\ {-}\frac{1}{5}=\frac{1}{{-}5};\)
      • \({\largeм)}\ \frac{3}{4}>{-}\frac{3}{4}.\)

    Задание 97Задание 99