Найдите сумму многочленов:
- \({\largeа)}\ (3a+5)+(2a-1)=\ \)
- \({\largeб)}\ (5x-2y)+(y-x)=\ \)
- \({\largeв)}\ (7a-2b+1)+(7a-2b+1)=\ \)
- \({\largeг)}\ (9x-y+7)+(y-7-x)=\ \)
- \({\largeд)}\ (a+b+c)+({-}a-b-c)=\ \)
- \({\largeе)}\ (a-2b+3c)+({-}3a+2b-c)=\ \)
Задание 139
Источник заимствования: Алгебра. Рабочая тетрадь. 7 класс. В 2 частях. Часть 1 / М.К. Потапов, А.В. Шевкин – Просвещение, 2018. – 51 c. ISBN 978-5-09-051661-7
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Решение:
- \({\largeа)}\ (3a+5)+(2a-1)=\)\(3a\)\(+\)\(5\)\(+\)\(2a\)\(-\)\(1\)\(=5a+4\)
- \({\largeб)}\ (5x-2y)+(y-x)=\)\(5x\)\(-\)\(2y\)\(+\)\(y\)\(-\)\(x\)\(=4x-y\)
- \({\largeв)}\ (7a-2b+1)+(7a-2b+1)=\)\(7a\)\(-\)\(2b\)\(+\)\(1\)\(+\)\(7a\)\(-\)\(2b\)\(+\)\(1\)\(=14a-4b+2\)
- \({\largeг)}\ (9x-y+7)+(y-7-x)=\)\(9x\)\(-\)\(y\)\(+\)\(7\)\(+\)\(y\)\(-\)\(7\)\(-\)\(x\)\(=8x\)
- \({\largeд)}\ (a+b+c)+({-}a-b-c)=\)\(a\)\(+\)\(b\)\(+\)\(c\)\(-\)\(a\)\(-\)\(b\)\(-\)\(c\)\(=0\)
- \({\largeе)}\ (a-2b+3c)+({-}3a+2b-c)=\)\(a\)\(-\)\(2b\)\(+\)\(3c\)\(-\)\(3a\)\(+\)\(2b\)\(-\)\(c\)\(={-}2a+2c\)