Задание 49

Запишите рациональное число в виде периодической дроби:

\({-}\frac{1}{2}={-}0{,}5={-}0{,}5(0);\phantom{00000000}{-}\frac{4}{9}={-}0{,}(4);\phantom{00000000}{-}\frac{4}{99}={-}0{,}(04)\)

\({\largeа)}\ {-}\frac{3}{4}=\phantom{0}\definecolor{dots}{RGB}{110,177,146}\color{dots}{\large...................}\)
\({\largeб)}\ {-}\frac{7}{9}=\phantom{0}\color{dots}{\large...................}\)

\({\largeв)}\ {-}\frac{25}{99}=\phantom{0}\color{dots}{\large..................}\)
\({\largeг)}\ {-}\frac{25}{33}=\phantom{0}\color{dots}{\large..................}\)

\({\largeд)}\ {-}\frac{2}{3}=\phantom{0}\color{dots}{\large...................}\)
\({\largeе)}\ {-}\frac{4}{11}=\phantom{0}\color{dots}{\large..................}\)

\({\largeж)}\ {-}\frac{5}{3}=\phantom{\ }\color{dots}{\large...................}\)
\({\largeз)}\ {-}\frac{12}{11}=\phantom{0}\color{dots}{\large..................}\)

\({\largeи)}\ {-}\frac{37}{33}=\phantom{\ }\color{dots}{\large..................}\)
\({\largeк)}\ {-}\frac{121}{999}=\phantom{0}\color{dots}{\large.................}\)

Источник заимствования: Алгебра. Рабочая тетрадь. 7 класс. В 2 частях. Часть 1 / М.К. Потапов, А.В. Шевкин – Просвещение, 2018. – 24 c. ISBN 978-5-09-051661-7

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Решение:

\({\largeа)}\ {-}\frac{3}{4}={-}0{,}75={-}0{,}75(0);\)
\({\largeб)}\ {-}\frac{7}{9}={-}0{,}(7);\)
\({\largeв)}\ {-}\frac{25}{99}={-}0{,}(25);\)
\({\largeг)}\ {-}\frac{25}{33}={-}\frac{75}{99}={-}0{,}(75);\)
\({\largeд)}\ {-}\frac{2}{3}={-}\frac{6}{9}={-}0{,}(6);\)
\({\largeе)}\ {-}\frac{4}{11}={-}\frac{36}{99}={-}0{,}(36);\)
\({\largeж)}\ {-}\frac{5}{3}={-}\frac{15}{9}={-}1\frac{6}{9}={-}1{,}(6);\)
\({\largeз)}\ {-}\frac{12}{11}={-}\frac{108}{99}={-}1\frac{9}{99}={-}1{,}(09);\)
\({\largeи)}\ {-}\frac{37}{33}={-}\frac{111}{99}={-}1\frac{12}{99}={-}1{,}(12);\)
\({\largeк)}\ {-}\frac{121}{999}={-}0{,}(121).\)

Задание 48*Задание 50