§ 3. Упражнение 600. «Математика. 6 класс. Учебник для общеобразовательных организаций. В 2 частях. Часть 1»

    Упражнение 600

    Найдите значение выражения:

      • $${\largeа)}\ 208{,}57-108{,}57:((60{,}4-57{,}6)\cdot(3{,}6+3{,}45));$$$${\largeб)}\ 565{,}3-465{,}3:((1{,}25+5{,}8)\cdot(55{,}8-49{,}2)).$$

    Источник заимствования: Математика. 6 класс. Учебник для общеобразовательных организаций. В 2 частях. Часть 1 / – Мнемозина, 2019. – 107 c. ISBN 978-5-346-03720-0
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    Решение:

      • $${\largeа)}\ 208{,}57-108{,}57:((60{,}4-57{,}6)\cdot(3{,}6+3{,}45))=208{,}57-108{,}57:(2{,}8\cdot(3{,}6+3{,}45))=208{,}57-108{,}57:(2{,}8\cdot7{,}05)=208{,}57-108{,}57:19{,}74=208{,}57-5{,}5=203{,}07$$

      • $$\begin{array}{}1)\\[3.5ex]\\\end{array}\begin{array}{r}-\begin{array}{r}60{,}4\\57{,}6\\\hline\end{array}\\\begin{array}{r}2{,}8\end{array}\end{array}$$
      • $$\begin{array}{}2)\\[3.5ex]\\\end{array}\begin{array}{r}+\begin{array}{r}3{,}60\\3{,}45\\\hline\end{array}\\\begin{array}{r}7{,}05\end{array}\end{array}$$
      • $$\begin{array}{}3)\\[10.5ex]\\\end{array}\begin{array}{r}\times\begin{array}{r}7{,}05\\2{,}8\\\hline\end{array}\phantom{0}\\\begin{array}{r}+\begin{array}{r}5640\\1410\phantom{0}\\\hline\end{array}\\\begin{array}{r}19{,}740\end{array}\end{array}\end{array}$$
      • $$\begin{array}{l}\begin{array}{}4)\\[0.2ex]\\\end{array}\begin{array}{r}-\begin{array}{l}10857{,}0\\\phantom{0}9870\\\hline\end{array}\begin{array}{|l}1974\\\hline5{,}5\end{array}\\\end{array}\\\phantom{\ 0000}\begin{array}{r}-\begin{array}{r}9870\\9870\\\hline\end{array}\end{array}\\\phantom{\ 000000000}\begin{array}{r}0\end{array}\end{array}$$
      • $$\begin{array}{}5)\\[3.5ex]\\\end{array}\begin{array}{r}-\begin{array}{r}208{,}57\\5{,}50\\\hline\end{array}\\\begin{array}{r}203{,}07\end{array}\end{array}$$

      • $${\largeб)}\ 565{,}3-465{,}3:((1{,}25+5{,}8)\cdot(55{,}8-49{,}2))=565{,}3-465{,}3:(7{,}05\cdot(55{,}8-49{,}2))=565{,}3-465{,}3:(7{,}05\cdot6{,}6)=565{,}3-465{,}3:46{,}53=565{,}3-10=555{,}3$$

      • $$\begin{array}{}1)\\[3.5ex]\\\end{array}\begin{array}{r}+\begin{array}{r}1{,}25\\5{,}80\\\hline\end{array}\\\begin{array}{r}7{,}05\end{array}\end{array}$$
      • $$\begin{array}{}2)\\[3.5ex]\\\end{array}\begin{array}{r}-\begin{array}{r}55{,}8\\49{,}2\\\hline\end{array}\\\begin{array}{r}6{,}6\end{array}\end{array}$$
      • $$\begin{array}{}3)\\[10.5ex]\\\end{array}\begin{array}{r}\times\begin{array}{r}7{,}05\\6{,}6\\\hline\end{array}\phantom{0}\\\begin{array}{r}+\begin{array}{r}4230\\4230\phantom{0}\\\hline\end{array}\\\begin{array}{r}46{,}530\end{array}\end{array}\end{array}$$
      • $$\begin{array}{l}\begin{array}{}4)\\[0.2ex]\\\end{array}\begin{array}{r}-\begin{array}{l}46530\\4653\\\hline\end{array}\begin{array}{|l}4653\\\hline10\end{array}\\\end{array}\\\phantom{\ 0000000}\begin{array}{r}0\end{array}\end{array}$$
      • $$\begin{array}{}5)\\[3.5ex]\\\end{array}\begin{array}{r}-\begin{array}{r}565{,}3\\10{,}0\\\hline\end{array}\\\begin{array}{r}555{,}3\end{array}\end{array}$$