§ 4. Упражнение 787. «Математика. 6 класс. Учебник для общеобразовательных организаций. В 2 частях. Часть 1»

    Упражнение 787

    Выполните действия:

      • $${\largeа)}\ (3{,}2:4+4\frac{4}{5}:3{,}2)\cdot4{,}8;$$$${\largeб)}\ (385{,}7:0{,}19-30)\cdot0{,}2-(35{,}7\cdot3{,}29+2{,}547).$$

    Источник заимствования: Математика. 6 класс. Учебник для общеобразовательных организаций. В 2 частях. Часть 1 / – Мнемозина, 2019. – 142 c. ISBN 978-5-346-03720-0
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    Решение:

      • $${\largeа)}\ (3{,}2:4+4\frac{4}{5}:3{,}2)\cdot4{,}8=(3{,}2:4+4{,}8:3{,}2)\cdot4{,}8=(0{,}8+4{,}8:3{,}2)\cdot4{,}8=(0{,}8+1{,}5)\cdot4{,}8=2{,}3\cdot4{,}8=11{,}04$$

      • $$\begin{array}{l}\begin{array}{}1)\\[0.2ex]\\\end{array}\begin{array}{r}-\begin{array}{l}3{,}2\\0\\\hline\end{array}\begin{array}{|l}4\\\hline0{,}8\end{array}\\\end{array}\\\phantom{\ 00}\begin{array}{r}-\begin{array}{r}32\\32\\\hline\end{array}\end{array}\\\phantom{\ 00000}\begin{array}{r}0\end{array}\end{array}$$
      • $$\begin{array}{l}\begin{array}{}2)\\[0.2ex]\\\end{array}\begin{array}{r}-\begin{array}{l}48{,}0\\32\\\hline\end{array}\begin{array}{|l}32\\\hline1{,}5\end{array}\\\end{array}\\\phantom{\ 00}\begin{array}{r}-\begin{array}{r}160\\160\\\hline\end{array}\end{array}\\\phantom{\ 000000}\begin{array}{r}0\end{array}\end{array}$$
      • $$\begin{array}{}3)\\[3.5ex]\\\end{array}\begin{array}{r}+\begin{array}{r}0{,}8\\1{,}5\\\hline\end{array}\\\begin{array}{r}2{,}3\end{array}\end{array}$$
      • $$\begin{array}{}4)\\[10.5ex]\\\end{array}\begin{array}{r}\times\begin{array}{r}2{,}3\\4{,}8\\\hline\end{array}\phantom{0}\\\begin{array}{r}+\begin{array}{r}184\\92\phantom{0}\\\hline\end{array}\\\begin{array}{r}11{,}04\end{array}\end{array}\end{array}$$

      • $${\largeб)}\ (385{,}7:0{,}19-30)\cdot0{,}2-(35{,}7\cdot3{,}29+2{,}547)=(2030-30)\cdot0{,}2-(35{,}7\cdot3{,}29+2{,}547)=2000\cdot0{,}2-(35{,}7\cdot3{,}29+2{,}547)=2000\cdot0{,}2-(117{,}453+2{,}547)=2000\cdot0{,}2-120=400-120=280$$

      • $$\begin{array}{l}\begin{array}{}1)\\[0.2ex]\\\end{array}\begin{array}{r}-\begin{array}{l}38570\\38\\\hline\end{array}\begin{array}{|l}19\\\hline2030\end{array}\\\end{array}\\\phantom{\ 0000}\begin{array}{r}-\begin{array}{r}5\\0\\\hline\end{array}\end{array}\\\phantom{\ 0000}\begin{array}{r}-\begin{array}{r}57\\57\\\hline\end{array}\end{array}\\\phantom{\ 0000000}\begin{array}{r}0\end{array}\end{array}$$
      • $$\begin{array}{}2)\\[3.5ex]\\\end{array}\begin{array}{r}-\begin{array}{r}2030\\30\\\hline\end{array}\\\begin{array}{r}2000\end{array}\end{array}$$
      • $$\begin{array}{}3)\\[13.5ex]\\\end{array}\begin{array}{r}\times\begin{array}{r}35{,}7\\3{,}29\\\hline\end{array}\phantom{0}\\\begin{array}{r}+\begin{array}{r}3213\\714\phantom{0}\\1071\phantom{00}\\\hline\end{array}\\\begin{array}{r}117{,}453\end{array}\end{array}\end{array}$$
      • $$\begin{array}{}4)\\[3.5ex]\\\end{array}\begin{array}{r}+\begin{array}{r}117{,}453\\2{,}547\\\hline\end{array}\\\begin{array}{r}120{,}000\end{array}\end{array}$$
      • $$\begin{array}{}5)\\[3.5ex]\\\end{array}\begin{array}{r}\times\begin{array}{r}2000\\0{,}2\phantom{000}\\\hline\end{array}\\\begin{array}{r}400{,}0\end{array}\end{array}$$
      • $$\begin{array}{}6)\\[3.5ex]\\\end{array}\begin{array}{r}-\begin{array}{r}400\\120\\\hline\end{array}\\\begin{array}{r}280\end{array}\end{array}$$